网上搜到的代码，千篇一律是这个

Function Sort(ary)
Dim KeepChecking,I,FirstValue,SecondValue
 KeepChecking = TRUE
Do Until KeepChecking = FALSE
 KeepChecking = FALSE
 For I = 0 to UBound(ary)
  If I = UBound(ary) Then Exit For
   If ary(I) > ary(I+1) Then
    FirstValue = ary(I)
    SecondValue = ary(I+1)
    ary(I) = SecondValue
    ary(I+1) = FirstValue
    KeepChecking = TRUE
   End If
 Next
Loop
 Sort = ary
End Function

存在错误。。。。。。

测试一下就知道

s="11,3,1"
s=sort(split(s,","))
for i=0 to ubound(s)
response.write s(i) & "<br>"
next

打印结果是

1

11

 3

 

正确的function是:

function sort(ary)
ck=true
do Until ck = false
 ck=false
 For f = 0 to UBound(ary) -1
  if clng(ary(f))>clng(ary(f+1)) then
   v1=clng(ary(f))
   v2=clng(ary(f+1))
   ary(f)=v2
   ary(f+1)=v1
   
   ck=true
  end if
 next
loop
sort=ary
end function

就差在一个clng()

但好笑的是，有些数组，用那个错误的sort函数是可以排正确的。